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If the 6th term of an A.P. is 46, find the sum of first 11 terms.​

Sagot :

Answer:

506

Step-by-step explanation:

:. t6 = 46 ... [ Given ]

tn = a+(n-1) d ... [ Formula ]

:. t6 = a+(6-1) d

:. 46 = a+5d ... [1]

Sn = n/2 [2a+(n-1)d] ... [ Formula ]

:. S11 = 11/2 [2a+(11-1) d]

:. S11 = 11/2 [2a+10d]

:. S11 = 11/2x2 [a+5d]

:. S11 = 11[46] ... [ From (1)]

:. S11 = 506