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Find the height of an equilateral triangle with side length 8.

Sagot :

prisha4princess

Answer:

U need to just do

[tex] \sqrt{3 \div 4} a {}^{2} [/tex]

Answer:

4[tex]\sqrt{5}[/tex]

Step-by-step explanation:

The segment from a vertex to the side opposite is a perpendicular bisector.

The equilateral Δ is divided into 2 right triangles with legs 8 and 4

let height be h, then using Pythagoras' identity

h² = 4² + 8² = 16 + 64 = 80 ( take the square root of both sides )

h = [tex]\sqrt{80}[/tex] = 4[tex]\sqrt{5}[/tex] ← exact value

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