Answered

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A 15 kg block is sliding along a frictionless surface and strikes a 10 kg ball at rest. What is the collision of the blocks after the collision if it is an inelastic collision?

Sagot :

Answer:

   v = 0.6 v₁

Explanation:

This is an exercise in collisions, let's start by defining a system formed by the two bodies, so that the forces during the collisions have been internal and the momentum is preserved.

Instant starts. Before the crash

       p₀ = M v₁ + m 0

Final moment. After the crash

       [tex]p_{f}[/tex] = (M + m) v

how momentum is conserved

       p₀ = p_{f}

       M v₁ = (M + m) v

       

       v = [tex]\frac{M}{M+m} v_{1}[/tex]

let's calculate

       v = [tex]\frac{15}{15+10} v_{1}[/tex]

        v = 0.6 v₁

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