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Write the equation of a line that is perpendicular to y=7x−2 and passes through the point (14,8).(1 point) y=7x−90 y=10x−17 y=−17x+1067 y=−17x+10

Sagot :

Answer:

[tex]\huge\boxed{y=-\frac{1}{7}x+ 10}[/tex]

Step-by-step explanation:

In order to find the equation of this line, we need to note two things.

  • A) The slope of two lines that are perpendicular will be opposite reciprocals (that is, multiplying them gets us -1.)
  • B) We can substitute a point inside an incomplete equation to try and find a missing value.

So first, let's find the opposite reciprocal of 7 which will be the slope to this equation.

  • Reciprocal of 7:    [tex]\frac{1}{7}[/tex]
  • Opposite of [tex]\frac{1}{7}[/tex]:    [tex]-\frac{1}{7}[/tex]

So the slope of this line will be [tex]-\frac{1}{7}[/tex]. The y-intercept will change, and we can substitute what we know into the equation [tex]y=mx+b[/tex].

[tex]y = -\frac{1}{7}x+b[/tex]

Now, we can substitute a point on the graph (14, 8) into this equation to find b.

  • [tex]8 = -\frac{1}{7} \cdot 14 + b[/tex]
  • [tex]8 = -\frac{14}{7} + b[/tex]
  • [tex]8 = -2 + b[/tex]
  • [tex]b = 10[/tex]

Now that we know the y-intercept, we can finish off our equation by plugging that in.

[tex]y = -\frac{1}{7}x + 10[/tex]

Hope this helped!

Answer:

y=−17x+10

Step-by-step explanation:

shorter version