Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

write an equation of the line passing through the point (3,2) and is parallel to the line y=\frac{1}{3}x-3


need answer ASAP

Sagot :

absor201

Answer:

Equation of line passing through (3,2) and parallel to line [tex]y = \frac{1}{3}x-3[/tex] is:

[tex]y = \frac{1}{3}x+1[/tex]

Step-by-step explanation:

Given equation of line is:

[tex]y = \frac{1}{3}x-3[/tex]

Slope-intercept form of a line is given by:

[tex]y = mx+b[/tex]

Comparing the given equation of line with general form we get

m = 1/3

Let m1 be the slope of line parallel to given line

Then the equation of line will be:

[tex]y = m_1x+b[/tex]

We know, "Slopes of two parallel lines are equal"

Which means

[tex]m_1 = m\\m_1 = \frac{1}{3}[/tex]

Putting the value of slope

[tex]y = \frac{1}{3}x+b[/tex]

Putting the point (3,2) in the equation

[tex]2 = \frac{1}{3}(3)+b\\2 = 1+b\\b = 2-1\\b = 1[/tex]

Final equation of line is:

[tex]y = \frac{1}{3}x+1[/tex]

Hence,

Equation of line passing through (3,2) and parallel to line [tex]y = \frac{1}{3}x-3[/tex] is:

[tex]y = \frac{1}{3}x+1[/tex]

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.