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Sagot :
Answer:
0.63 m/s²
Explanation:
Given that
Distance of meteor from earth's surface, r = 2.98R,
where R = radius of the Earth.
The force of the meteor due to the Earth is usually given by
F = GMM(a)/(R + r)² where
F = force exerted
G = gravitational constant
M = Mass of the earth
M(a) = mass of meteor
Remember that F = Ma, so applying that here, we have
acceleration of meteor = GM/(R + r)²
where r = 2.98R so that
acceleration of meteor = GM/(R + 2.98R)²
acceleration of meteor = GM/(3.98R)²
acceleration of meteor = GM / 15.84R²
It should be noted that GM/R² = 10, so
acceleration of meteor = 10/15.84
acceleration of meteor = 0.63 m/s²
Therefore as calculated, the acceleration of the meteor is 0.63 m/s²
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