Answer:
[tex] \sqrt{ {8}^{2} +{10}^{2} } = \sqrt{64 + 100} = \sqrt{164} =2\sqrt{41}\\ =\boxed{12.8\: units} [/tex]
The diagonal length of the rectangular book is 12.8 units.
A rectangle is "four sided polygon, having all the internal angles is equal to 90 degree. The two sides of each corner is right angles".
According to the question,
The length of rectangle is 8 units and the breadth of rectangle is 10 cm.
To find diagonal of the rectangle: Using Pythagoras theorem a² + b² = c².
c = [tex]\sqrt{a^2 + b^2}[/tex]
= [tex]\sqrt{8^2 + 10^2}[/tex]
= [tex]\sqrt{64 + 100}[/tex]
= [tex]\sqrt{164}[/tex]
= 2[tex]\sqrt{41}[/tex]
= 12.8 units
Hence, the diagonal length of the rectangular book is 12.8 units.
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