Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

CAN SOMEONE PLS HELP WITH THIS ASAP

CAN SOMEONE PLS HELP WITH THIS ASAP class=

Sagot :

rebeccarayshma

Answer:

the second option

Step-by-step explanation:

[tex] \sin(theta) = \frac{opposite}{hypotenuse} [/tex]

[tex] \cos(theta) = \frac{adjacent}{hypotenuse} [/tex]

[tex] \tan(theta) = \frac{opposite}{adjacent} [/tex]

theta = 45°

hypotenuse = 9

opposite = x

find x using the sin formula

[tex] \sin(theta) = \frac{opposite}{hypotenuse} [/tex]

[tex] \sin(45) = \frac{x}{9} [/tex]

[tex] \sin(45) \times 9 = x[/tex]

[tex] \frac{9 \sqrt{2} }{2} = x[/tex]

[tex]x = \frac{9 \sqrt{2} }{2} [/tex]

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.