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the question is a picture pls help

The Question Is A Picture Pls Help class=

Sagot :

The unknown alcohol = 2-propanol

Further explanation

Given

volume = 50 ml

mass = 39.4 g

Required

The unknown alcohol

Solution

Density of sample :

= mass : volume

= 39.4 g : 50 ml

= 0.788 g/ml

The unknown alcohol at room temperature = liquid, so the unknown alcohol is 2-propanol because it has temperature range between -90 to 82 for liquid and the density = 0.788 g/ml