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Sagot :

Answer:

2H2S + 3O2 --> 2H2O + 2SO2

2 mol H2S/8 mol H2O = 0.25 mol

Explanation:

Reactants: H is 2; S is 1; O is 2

Products: H is 2; S is 1; O is 3

There are 3 oxygens so add a 2 to the H2O e and 3 to the reactants side.

H2S + 3O2 → 2H2O + SO2

Reactant side: H is 2; S is 1; O is 6

Product side: H is 4; S is 1; O is 4

Hydrogen is now out of balance, so a coefficient of 2 can be placed in front of H2S to give:

2H2S + 3O2 → 2H2O + SO2

Reactant side: H is 4; S is 2; O is 6

Product side: H is 4; S is 1; O is 4

Sulfur is unbalanced, so a coefficient of 2 can be placed in front of SO2 to give:

2H2S + 3O2 → 2H2O + 2SO2

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