Answered

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g(x)=x^2+3x-3
What are the zeros of the function?

Sagot :

clarch19

Answer:

(-3+[tex]\sqrt{21}[/tex]) /2,  (3+[tex]\sqrt{21}[/tex]) / 2 which is approx -3.791 and 0.791

Step-by-step explanation:

i used the quadratic formula:  [-b± sq rt (b² - 4ac) / 2a]

in this problem, a = 1, b = 3, and c = -3

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