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In AGHI, GI is extended through point I to point J, mZGHI = (2x - 3)º,
mZIGH = (2x + 15)°, and m_HIJ = (7x – 18)'. Find mZGHI.

In AGHI GI Is Extended Through Point I To Point J MZGHI 2x 3º MZIGH 2x 15 And MHIJ 7x 18 Find MZGHI class=

Sagot :

akposevictor

Answer:

m<GHI = 17°

Step-by-step explanation:

m<GHI = (2x - 3)°

m<IGH = (2x + 15)°

m<HIJ = (7x - 18)°

<HIJ is an exterior angle of ∆GHI

<GHI and <HIJ are both interior angles of ∆GHI that are opposite to the exterior angle.

Therefore, based on the exterior angle theorem of a triangle, we would have the following equation:

m<GHI + m<IGH = m<HIJ

(2x - 3)° + (2x + 15)° = (7x - 18)° (substitution)

Solve for x

2x - 3 + 2x + 15 = 7x - 18

Add like terms

4x + 12 = 7x - 18

4x - 7x = -12 - 18

-3x = -30

Divide both sides by -3

x = 10

✔️m<GHI = (2x - 3)°

Plug in the value of x

m<GHI = 2(10) - 3 = 20 - 3

m<GHI = 17°

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