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Sagot :
Answer:
1. 9.338×10¯⁶ N
2. 5.28×10¯¹⁰ N
Explanation:
1. Determination of the force
Mass of 1st object (M₁) = 70 Kg
Mass of 2nd object (M₂) = 2000 Kg
Distance apart (r) = 1 m
Gravitational constant (G) = 6.67×10¯¹¹ Mm²/Kg²
F = GM₁M₂ / r²
F = 6.67×10¯¹¹ × 70 × 2000 / 1²
F = 6.67×10¯¹¹ × 70 × 2000 / 1
F = 9.338×10¯⁶ N
2. Determination of the force.
Mass of 1st fruit (M₁) = 0.45 Kg
Mass of 2nd fruit (M₂) = 0.45 Kg
Distance apart (r) = sum of their radius = 0.08 + 0.08 = 0.16 m
Gravitational constant (G) = 6.67×10¯¹¹ Mm²/Kg²
F = GM₁M₂ / r²
F = 6.67×10¯¹¹ × 0.45 × 0.45 / 0.16²
F = 6.67×10¯¹¹ × 0.45 × 0.45 / 0.0256
F = 5.28×10¯¹⁰ N
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