Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
[tex][NO]=\frac{k_{-1}}{k_1} [N_2O_2][/tex]
Explanation:
Hello!
In this case, since the reaction may be assumed in chemical equilibrium, we can write up the rate law as shown below:
[tex]r=-k_1[NO]+k_{-1}[N_2O_2][/tex]
However, since the rate of reaction at equilibrium is zero, due to the fact that the concentrations remains the same, we can write:
[tex]0=-k_1[NO]+k_{-1}[N_2O_2][/tex]
Which can be also written as:
[tex]k_1[NO]=k_{-1}[N_2O_2][/tex]
Then, we solve for the concentration of NO to obtain:
[tex][NO]=\frac{k_{-1}}{k_1} [N_2O_2][/tex]
Best regards!
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.