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(points on a circle) PLEASE HELP THIS IS DUE TONIGHT
A circle is centered at C(0,0)C(0,0)C, left parenthesis, 0, comma, 0, right parenthesis. The point M(0,\sqrt{38})M(0,38 )M, left parenthesis, 0, comma, square root of, 38, end square root, right parenthesis is on the circle.

Where does the point N(-5,-3)N(−5,−3)N, left parenthesis, minus, 5, comma, minus, 3, right parenthesis lie?

Sagot :

Answer:

Inside the circle, a distance of [tex]\sqrt{34}[/tex] from the center of the circle.

Step-by-step explanation:

Center of circle is at (0,0)

One point of the circle is at (0,[tex]\sqrt{38}[/tex])

Since the only known point is in the y-axis, the radius of the circle must be [tex]\sqrt{38}[/tex].

[tex]\sqrt{38}[/tex] = 6.164

So the point (-5,-3) is still inside the circle as the distance from point (-5,-3) to the center of the circle is [tex]\sqrt{(5)^2+(-3)^2}[/tex] or [tex]\sqrt{34}[/tex] which is less than the radius of the circle.

Answer: inside the circle, I answered on khan, and have a picture to prove it, see below

Step-by-step explanation:

View image copperdog1011