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2.)
Find the perimeter of an isosceles triangle whose base is 16 cm and whose height is 15 cm.

Sagot :

Answer:

50 cm

Step-by-step explanation:

The altitude from the vertex to the base bisects the base and divides the triangle into 2 right triangles.

Using one of the right triangles with legs 8 and 15 , then hypotenuse h is

h² = 8² + 15² = 64 + 225 = 289 ( take the square root of both sides )

h = [tex]\sqrt{289}[/tex] = 17

The 2 congruent sides of the isosceles triangle are 17 cm

Then the perimeter P is

P  = 17 + 17 + 16 = 50 cm