At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
[tex]f^{-1}(x) = \frac{x+8}{8}[/tex]
Domain of f(x): All real values.
Range of f(x): All real values.
Domain of f -1(x): All real values.
Range of f -1(x): All real values
Step-by-step explanation:
We are given the following function:
[tex]f(x) = 8x + 8[/tex]
Since it is a line, we have that both the domain is the range is the real set.
Inverse function:
The domain of the inverse function is the range of the original function, and the range of the inverse function is the domain of the original function.
Finding the inverse function:
Exchange x and y in the original function, and isolate y. So
Original
[tex]y = 8x + 8[/tex]
Exchanging:
[tex]x = 8y - 8[/tex]
Isolating y:
[tex]8y = x + 8[/tex]
[tex]y = \frac{x+8}{8}[/tex]
[tex]f^{-1}(x) = \frac{x+8}{8}[/tex]
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
