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Sagot :
The diagram of the triangle is missing, so i have attached it.
Answer:
PN = 28
QP = 14
Step-by-step explanation:
We are told that QN = 42
Since P is the centroid, by inspection we can see that;
PN = ⅔QN
Thus, PN = ⅔ × 42
PN = 28
Also, we see that PN + QP = QN
Thus;
28 + QP = 42
QP = 42 - 28
QP = 14
Following are the calculation on the PN and QP:
- Mp, Lp, and NQ are indeed the central lines of a large briangle MNL, according the problem. Particles entersect at point P.
- This is referred to as a baryc enter of a friangle.
- And has the quality Np= 2PQ, therefore we can obtain it.
[tex]Np = \frac{2}{3} QN\\\\ PQ = \frac{1}{3} QN \\\\NP=\frac{2}{3} \times 42= 28 \\\\PQ= \frac{1}{3} \times 42 = 14 \\\\[/tex]
- When you are aware, the point p is indeed the barycenter of a large triangle, and this is an important trait.
Learn more:
brainly.com/question/80336
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