Answered

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Part A
Consider the following balanced reaction: N2(g) + 3 H2(9) - 2 NH3(9) How many moles of NH3 could be produced from 0.500 mol of H2?

Sagot :

Eduard22sly

Answer:

0.33 mole of NH₃

Explanation:

The balanced equation for the reaction is given below:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles of NH₃

Finally, we shall determine the number of mole of NH₃ that will be produced by the reaction of 0.5 moles of H₂. This can be obtained as follow:

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles of NH₃

Therefore, 0.5 moles of H₂ will react to produce = (0.5 × 2)/3 = 0.33 mole of NH₃.

Thus, 0.33 mole of NH₃ was obtained from the reaction

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