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Need help on algebra hw question.

Need Help On Algebra Hw Question class=

Sagot :

Answer:  C) 5

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Work Shown:

s = square side length

A = area of square = 9x^2+12x+4

A = s^2

A = (ax+b)^2

A = a^2*x^2 + 2abx + b^2 .... apply the FOIL rule

A = 9x^2 + 12x + 4

Equating corresponding terms, we see that,

  • a^2*x^2 = 9x^2 which shows that a^2 = 9 and that solves to a = 3, assuming 'a' is positive.
  • 2abx = 12x leads to 2ab = 12 or ab = 6. Using a = 3 we can find that b = 2.
  • b^2 = 4 solves to b = 2 which matches with the previous value of b found.

Using a = 3 and b = 2, the sum of the values is a+b = 3+2 = 5, so that's why the answer is choice C.

Side note: 9x^2 + 12x + 4 factors to (3x + 2)^2

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