Answered

Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

2. If k is a constant, what is the value of k such that the polynomial k2x3 - 6kx+9 is divisible by x - 1?

Sagot :

JeanaShupp

Answer: The value of k =3.

Step-by-step explanation:

According to factor theorem, if g(x) =x-a is a factor of p(x) then p(a)=0.

Given: [tex]x-1[/tex] is a factor of [tex]k^2x^3-6kx+9[/tex].

then

[tex]k^2(1)^3-6k(1)+9=0\\\\\Rightarrow\ k^2-6k+9=0\\\\\Rightarrow\ k^2-3k-3k+9=0\\\\\Rightarrow\ k(k-3)-3(k-3)=0\\\\\Rightarrow\ (k-3)(k-3)=0\\\\\Rightarrow\ k=3[/tex]

Hence, the value of k =3.

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.