Answered

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A bike tire at a pressure of 740 mmHg and a
temperature of 290 K has a volume of 2.2 liters.
A child gets on the bike and rides it outside.
What is the new pressure if the temperature
outside is 296 K and his weight causes the tire's
volume to drop to 2.0 liters?

Sagot :

Answer: The new pressure is 831 mm Hg

Explanation:

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 740 mm Hg

[tex]P_2[/tex] = final pressure of gas = ?

[tex]V_1[/tex] = initial volume of gas = 2.2 L

[tex]V_2[/tex] = final volume of gas = 2.0 L

[tex]T_1[/tex] = initial temperature of gas = 290 K

[tex]T_2[/tex] = final temperature of gas = 296 K

Now put all the given values in the above equation, we get:

[tex]\frac{740\times 2.2}{290}=\frac{P_2\times 2.0}{296}[/tex]

[tex]P_2=831mmHg[/tex]

The new pressure is 831 mm Hg

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