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please help with maths work

Please Help With Maths Work class=

Sagot :

Given:

In a right angle triangle ABC, [tex]\angle B=90^\circ,x=8.7\ m[/tex], and [tex]\theta = 45^\circ[/tex]

To find:

The value of AC.

Solution:

In a right angle triangle,

[tex]\cos \theta =\dfrac{Adjacent}{Hypotenuse}[/tex]

[tex]\cos \theta =\dfrac{BC}{AC}[/tex]

[tex]\cos (45^\circ) =\dfrac{8.7}{AC}[/tex]

[tex]\dfrac{1}{\sqrt{2}}=\dfrac{8.7}{AC}[/tex]

On cross multiplication, we get

[tex]AC=8.7\times \sqrt{2}[/tex]

[tex]AC=12.30365799[/tex]

[tex]AC\approx 12.304[/tex]

Therefore, the measure of AC is 12.304 m.

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