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The area of a piston of a force pump is 8 X 10⁴m². What force must be
applied to the piston to raise oil (d = 780 Kg/mº) to a height of 6.0 m? Assume
the upper end of the oil is open to the atmosphere.​

Sagot :

Answer:

Force of [tex]37.44 * 10^{8}[/tex] Kgm/s^2 must be  applied to the piston to raise oil to a height of 6.0 m

Explanation:

As we know,

Pressure is the force per unit area

Or [tex]P = \frac{F}{A}[/tex]

Force [tex]= P * A[/tex]

Pressure is the product of density, gravitational constant and height

[tex]P = 780 * 10 * 6[/tex]

Force

[tex]= P * A\\= 780 * 10*6*8*10^4\\= 37.44 * 10^{8}[/tex]Kgm/s^2

The force that must be applied to the piston to raise oil will be 37.44 ×10⁸ N. Force is defined as the ratio of presure and area. Its unit is Newton.

What is force?

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The given data in the problem is;

A is the area of a piston = 8 X 10⁴m².

F is the force=?

h is the height = 6.0 m

Force is defined as the ratio of presure and area. Its unit is Newton.

[tex]\rm P = \frac{F}{A} \\\\ \rm F = P \times A \\\\ \rm F = 780 \times 10^6 \times 8 \times 10^4 \\\\ \rm F = 37.44 \times 10^8[/tex]

Hence the force that must be applied to the piston to raise oil will be 37.44 ×10⁸ N.

To learn more about the force refer to the link;

https://brainly.com/question/26115859