pmcdowell38
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Patients come into a medical clinic have a mean weight of 207.6 pounds with a standard deviation of 22.6 pounds. the distribution of weight is not assumed to be symmetric. between what two ways does Chebyshev's Theorem guarantee that we will find at least 95% of the patients? Round your answers to the nearest 10th

Sagot :

I know the answer it is 98.2

Answer: 105.9 lbs and 309.3 lbs

Step-by-step explanation:

By Chebyshev's Theorem, the proportion of patients with weights within 4.5 standard deviations of the mean is at least 95%.  Therefore k=4.5.

The weight that is 4.5 standard deviations less than the mean is 207.6−4.5(22.6)=105.9 pounds.

The weight that is 4.5 standard deviations greater than the mean is 207.6+4.5(22.6)=309.3 pounds.

So at least 95% of the patients have weights between 105.9 and 309.3 pounds.

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