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PLS ANSWER ASAP ILL APPRECIATE IT A LOT!!
please explain in details how u did do u could !!!

PLS ANSWER ASAP ILL APPRECIATE IT A LOT Please Explain In Details How U Did Do U Could class=

Sagot :

hamzaahmeds

Answer:

a) W = - 3387525.12 J = - 3.39 MJ

b) F = - 19031.04 N = - 19 KN

Explanation:

First, we need to find the deceleration of the rocket by using the third equation of motion:

[tex]2as = v_{f}^2 - v_{i}^2\\[/tex]

where,

a = deceleration = ?

s = distance covered = 178 m

vf = final speed = 0 m/s

vi = 284 m/s

Therefore,

[tex]2a(178\ m) = (0\ m/s)^2 - (284\ m/s)^2\\a = \frac{-(284\ m/s)^2)}{(2)(178\ m)}\\\\[/tex]

a = 226.56 m/s²

b)

Now, we can find the force by Newton's Second Law:

[tex]F = ma\\F = (84\ kg)(-226.56\ m/s^2)\\[/tex]

F = - 19031.04 N = - 19 KN

Here, negative sign shows braking force.

a)

For work done:

[tex]Work = W = Fs\\W = (-19031.04\ N)(178\ m)\\[/tex]

W = - 3387525.12 J = - 3.39 MJ

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