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Consider the following correct implementation of the selection sort algorithm.
public static void selectionSort(int[] elements)

{
for (int j = 0; j < elements.length - 1; j++)
{
int minIndex = j;
for (int k = j + 1; k < elements.length; k++)
{
if (elements[k] < elements[minIndex])
{
minIndex = k;
}
}
if (j != minIndex)
{
int temp = elements[j];
elements[j] = elements[minIndex];
elements[minIndex] = temp; // line 19
}
}
}
The following declaration and method call appear in a method in the same class as selectionSort.

int[] arr = {30, 40, 10, 50, 20};
selectionSort(arr);

How many times is the statement elements[minIndex] = temp; in line 19 of the method executed as a result of the call to selectionSort ?

a. 1
b. 2
c. 3
d. 4
e. 5

Sagot :

sandlee09

Answer:

c. 3

Explanation:

The line of code on line 19

elements[minIndex] = temp;

will run a total of 3 times in with this call to the selectionSort method. The first time it will turn the 10 in position 2 into a 30. The second time it will turn the 20 in position 4 into a 40. Finally, it will turn the newly positioned 40 in position 4 into a 50. Therefore, completely sorting the array's elements.

MrRoyal

The statement elements[minIndex] = temp; in line 19 of the method is executed 3 times as a result of the call to selectionSort

The array is declared as:

int[] arr = {30, 40, 10, 50, 20};

To sort the above array, the selectionSort algorithm would

  1. swap the positions of 10 and 30
  2. swap the positions of 20 and 40
  3. swap the positions of 50 and the new position of 40

Hence, the selectionSort algorithm would execute line 19 3 times

Read more about algorithms at:

https://brainly.com/question/15263760

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