Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Given the polynomial find any actual rational roots
x^3+x^2+4x+4=0

Sagot :

hellocrisco8

https://brainly.com/question/7356967 the correct answer is there Part 1A:

Given

Part 1B:

Given

Using rational roots theorem, we can see that the possible roots of the the given equation are:

By substituting the possible roots, we can see that x = 1 is a root, thus x - 1 is a factor.

We can get the other factors by using sythetic division to divide  by x - 1.

Step-by-step explanation:

x^3+x^2+4x+4=0

x³+x²+4x=-4

x(x²+x+4)=-4

either

x=-4

or

x²+x+4=-4

x²+x+4+4=0

x²+x+8=0

comparing with ax² +bx+c

a=1

b=1

c=8

x={-1±√{1²-4×1×8}}/2×1

x={-1±√{-31}}/2

View image Аноним
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.