Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Given the polynomial find any actual rational roots
x^3+x^2+4x+4=0

Sagot :

hellocrisco8

https://brainly.com/question/7356967 the correct answer is there Part 1A:

Given

Part 1B:

Given

Using rational roots theorem, we can see that the possible roots of the the given equation are:

By substituting the possible roots, we can see that x = 1 is a root, thus x - 1 is a factor.

We can get the other factors by using sythetic division to divide  by x - 1.

Step-by-step explanation:

x^3+x^2+4x+4=0

x³+x²+4x=-4

x(x²+x+4)=-4

either

x=-4

or

x²+x+4=-4

x²+x+4+4=0

x²+x+8=0

comparing with ax² +bx+c

a=1

b=1

c=8

x={-1±√{1²-4×1×8}}/2×1

x={-1±√{-31}}/2

View image Аноним
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.