Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
a) 208.33 A
b) 1.152 Ω
c) 0.03456 Ω
d) 6943.64 A
Explanation:
Transformer ratings :
Base power ( Sb ) = 50 KVA ,
Transformer voltage = 2400 / 240 V ,
Impedance ( Zp.u ) = 3.0 % = 0.03
phase = single ( 1 ) phase
Base Voltage on low side ( Vb ) = 240 V
a) Calculate the base current ( Ib )
Ib = Sb / Vb = ( 50 * 10^3 ) / 240
= 208.33 A
b) calculate base impedance ( Zb )
Zb = Vb^2 / Sb = ( 240 )^2 / 50000
= 1.152 Ω
c) Calculate the actual impedance ( Zact )
Zact = Zp.u * Zbase
= 0.03 * 1.152 = 0.03456 Ω
d) Calculate the short circuit current ( Isc )
Isc = Vp.u / Zp.u
= 1 / 0.03 = 33.33 p.u
therefore Isc = 33.33 * Ib
= 33.33 * 208.33 = 6943.64 A
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.