nicholasrflores07
Answered

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Johnny is designing a playground model for a school project. the design below will be the foundation of his model. what is the area of the model John design? use 3.14 for p.​

Johnny Is Designing A Playground Model For A School Project The Design Below Will Be The Foundation Of His Model What Is The Area Of The Model John Design Use 3 class=

Sagot :

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Answer:

586.17

Step-by-step explanation:

Area of triangle = 1/2 x base x height

[tex] = \frac{1}{2} \times 18 \times 7 \\ = \frac{1}{2} \times 126 \\ = 63 {cm}^{2} [/tex]

Area of Rectangle = Length x Width

[tex] = 22 \times 18 \\ = 396 {cm}^{2} [/tex]

Area of Semicircle =

[tex] \frac{1}{2} \pi {r}^{2} \\ = \frac{1}{2} (3.14)(9) {}^{2} \\ = 127.17cm {}^{2} [/tex]

Total Area = Area of Triangle + Area of Rectangle + Area of Semicircle

[tex] = 63 + 396 + 127.17 \\ = 586.17cm {}^{2} [/tex]

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