Answer:
a = 6.25 m/s/s
d = 50 m
Explanation:
Given:
v1 (initial velocity)= 0 m/s (cz its at rest)
v2 (final velocity)= 25 m/s
t = 4s
a = ?
d = ?
to determine acceleration
a = (v2 - v1)/ t
= (25m/s - 0m/s)/4s
= 6.25 m/s/s
to determine distance traveled
d = 1/2(v1 + v2)t
=1/2(0m/s+25m/s)(4s)
=50 m
Answer:
Answer in explanation.
Explanation:
Using Equation
[tex]v = u + at[/tex]
where v is the final velocity
u is initial velocity
a is acceleration
t is time taken
given u = 0, v = 25, t = 4,
[tex]25 = 0 + 4a \\ 4a = 25 \\ a = 6.25 \frac{m}{ {s}^{2} } [/tex]
Now, using equation
[tex]v {}^{2} = {u}^{2} + 2as[/tex]
where v and u remains the same, a = 6.25 and s is the distance,
[tex](25) {}^{2} = \: {0}^{2} + 2(6.25)s \\ 12.5s = 625 \\ s = \frac{625}{12.5} \\ s = 50m[/tex]
