Silem2020
Answered

Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

i dont know how to solve this questions without a graphing on a calculator but i can't use calculator for this question pls help

I Dont Know How To Solve This Questions Without A Graphing On A Calculator But I Cant Use Calculator For This Question Pls Help class=

Sagot :

Averysmartperson

Answer:

D

Step-by-step explanation:

When the denominator is equal to 0, the function doesn't exist. So factor the bottom, luckily its already partially factored.

(x^2 + 8x + 12) = (x+2)(x+6)

So now the denominator is (x+2)(x+6)(x-3)

The function doesn't exist when x = -2, -6, 3

Now we know there are 3 total discontinuities.

A and B can be eliminated

Since there is an (x+2) on the top and the bottom, they don't affect the shape of the function, but only causes a removable discontinuity when x = -2.

However, (x+6) and (x-3) are only on the bottom, so they DO change the shape, so they are non-removable

The answer therefore is 1 removable and 2 non-removable; D

mirai123

Answer:

We have 1 removable discontinuity and 2 non-removable discontinuities

Step-by-step explanation:

Note that

[tex]x^2+8x+12 = (x+2)(x+6)[/tex]

Initially, we have discontinuities at

[tex]x = -2; x = -6; x = 3[/tex]

Considering

[tex]f(x)=\dfrac{(x+2)(x-6)}{(x^2+8x+12)(x-3)}[/tex]

But

[tex]\dfrac{(x+2)(x-6)}{(x^2+8x+12)(x-3)}= \dfrac{(x+2)(x-6)}{ (x+2)(x+6)(x-3)}= \dfrac{(x-6)}{ (x+6)(x-3)}[/tex]

We have now two discontinuities at

[tex]x = -6; x = 3[/tex]

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.