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Show that solving the equation 3^2x=4 by taking common logarithms of both sides is equivalent to solving it by taking logarithms of base 3 of both sides.

Sagot :

altavistard

Answer:

Step-by-step explanation:

Case I:  use common logs:

 2x log 3 = log 4, or 2x(0.47712) = 0.60206

 Solving for x, we get 0.95424x = 0.60206, and then x = 0.60206/0.95424.

 x is then x = 0.631

Case II:  use logs to the base 3:

 2x (log to the base 3 of 3) = (log to the base 3 of 4)

 This simplifies to 2x(1) = 2x = (log 4)/log 3 = 1.262.  Finally, we divide this

 result by 2, obtaining x = 0.631

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