Answered

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what is the power output needed from a motor to lift in the absence of friction a mass of 1.5 ×10⁴ kg 25 m in 6.0 s at constant speed​

Sagot :

Answer:

the power output needed is  61.25 × 10⁴

Explanation:

The computation of the power output needed is shown below;

Given that

m =  1.5 ×10⁴ kg

v = 25m  ÷ 6.0 s

And g = 9.8 m/sec^2

Now based on the above information

p = f × v

= mg × v

= 1.5 ×10⁴ × 9.8 × 25 ÷ 6

= 61.25 × 10⁴

Hence, the power output needed is  61.25 × 10⁴

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