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calculate the value of (Ag+) in a saturated solution of AgCl in distilled water

Sagot :

sebassandin

Answer:

[tex][Ag^+]=1.3x10^{-5}M[/tex]

Explanation:

Hello there!

In this case, according to the dissociation of silver chloride in aqueous solution, we can write:

[tex]AgCl(s)\rightarrow Ag^+(aq)+Cl^-(aq)[/tex]

Whereas the equilibrium expression is:

[tex]Ksp=[Ag^+][Cl^-][/tex]

And the solubility product constant is  1.7 x10⁻¹⁰; thus, by inserting x as the concentration of both silver and chloride ions as they are the same at equilibrium, we obtain:

[tex]1.7x10^{-10}=x^2\\\\x=\sqrt{1.7x10^{-10}} \\x=1.3x10^{-5}M[/tex]

Which is also equal to the concentration silver ions at equilibrium in a saturated solution because we considered the Ksp.

[tex][Ag^+]=1.3x10^{-5}M[/tex]

Best regards!

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