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A bulb plugged into a 110V wall socket has a resistance of 200 Ω. Calculate the how many seconds it will take to pass 2500 C of charge. USE GRASP methoth PLSSSS

Sagot :

Cricetus

Answer:

The right solution is "4545.45 seconds".

Explanation:

The given values are:

Charge,

C = 2500 C

Resistance,

R = 200 Ω

Bulb plugged into,

V = 110 V

As we know,

⇒  [tex]I=\frac{V}{R}[/tex]

On substituting the values, we get

⇒     [tex]=\frac{110}{200}[/tex]

⇒     [tex]=0.55 \ A[/tex]

Now,

⇒  [tex]Q=I\times t[/tex]

or,

⇒  [tex]t=\frac{Q}{I}[/tex]

On substituting the values, we get

⇒     [tex]=\frac{2500}{0.55}[/tex]

⇒     [tex]=4545.45 \ seconds[/tex]

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