Answered

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A shelf is designed so it will fit in a 90º corner between two walls. The shelf has dimensions, rounded to the nearest tenth, as shown. A triangle has side lengths 11 centimeters, 11 centimeters, and hypotenuse of StartRoot 242 EndRoot centimeters. [Not drawn to scale] Will the shelf fit snugly in a 90º corner?

Sagot :

MrRoyal

Answer:

Yes, it will fit snugly in a 90º corner

Step-by-step explanation:

To do this, we simply need to check if the given sides of the shelf is right-angled.

So, we have:

[tex]Hypotenuse = \sqrt{242[/tex]

[tex]Side\ 1 = Side\ 2 = 11[/tex]

To check for right-angle triangle, we make use of:

[tex]Side\ 1^2 + Side\ 2^2 = Hypotenuse^2[/tex]

This gives:

[tex]11^2 + 11^2 = \sqrt{242}^2[/tex]

[tex]121 + 121 = \sqrt{242}^2[/tex]

[tex]242 = \sqrt{242}^2[/tex]

[tex]242 = 242[/tex]

This shows that the given sides of the shelf is a right-angled triangle.

Hence, it will fit the wall

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