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9.16 liters of CO2 weighs how many grams?

Your answer

Sagot :

Answer:

18.0g of CO₂ are present in 9.16L

Explanation:

To solve this question we must use:

PV = nRT

In order to find the moles of the gas and with its molar mass (44.01g/mol for CO₂) we can find the mass of the gas

Assuming STP conditions:

P = 1atm at STP

V = 9.16L

n are the moles of CO₂

R = 0.082atmL/molK

T = 273.15K

Replacing:

PV / RT = n

1atm*9.16L / 0.082atmL/molK*273.15K = n

0.409 moles = Moles of CO₂

The mass is:

0.409 moles CO₂ * (44.01g / mol) =

18.0g of CO₂ are present in 9.16L

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