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What is the molarity of a solution containing 3.6 mol of KCl in 750 mL?

Sagot :

Sarah06109

Answer:

[tex]\boxed {\boxed {\sf 4.8 \ M \ KCl}}[/tex]

Explanation:

The molarity of a solution is found by dividing the moles of solute by the liters. of solvent.

[tex]molarity=\frac{moles}{liters}[/tex]

We know the solution has 3.6 moles of potassium chlorine. We know there are 750 milliliters of solvent, but we need to convert this to liters.

  • 1 liter is equal to 1000 milliliters. Set up a proportion.
  • [tex]\frac {1 \ L }{1000 \ mL}[/tex]
  • Multiply by 750 mL and the units of mL will cancel.
  • [tex]750 \ mL * \frac {1 \ L }{1000 \ mL} = \frac {750 \ mL}{1000 \ mL}= 0.75 \ L[/tex]

Now we know the moles and liters, so we can calculate molarity.

  • moles= 3.6 mol KCl
  • liters= 0.75 L

Substitute these values into the formula.

[tex]molarity= \frac{3.6 \ mol \ KCl}{0.75 \ L}[/tex]

Divide.

[tex]molarity= 4.8 \ mol \ KCl/ L[/tex]

  • 1 mole per liter is equal to 1 molar.
  • Our answer of 4.8 moles of potassium chloride per liter is equal to 4.8 M KCl

[tex]molarity= 4.8 \ M \ KCl[/tex]

The molarity of the solution is 4.8 M KCl.

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