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The identity (x2 + y2) = (x2 - y2) + (2xy)? can be used to generate Pythagorean triples. What
Pythagorean triple could be generated using x=8 and y=3

Sagot :

Answer: 5329, 3025, 2304

Step-by-step explanation:

I just did the test

Pythagorean triple generated is 5329

What is Pythagorean triple?

A Pythagorean triple consists of three positive integers a, b, and c, such that a² + b² = c². Such a triple is commonly written, and a well-known example is. If is a Pythagorean triple, then so is for any positive integer k. A primitive Pythagorean triple is one in which a, b and c are coprime

We have,

([tex]x^{2}[/tex]+[tex]y^{2}[/tex] )=( [tex]x^{2}[/tex]-[tex]y^{2}[/tex]) + [tex]2xy[/tex]

Using Points,

x =8, y=3

According to the questions

Taking square in both sides

[tex](x^{2} + y^{2}) ^{2}[/tex] = [tex](x^{2} - y^{2} ) ^{2}[/tex] + [tex](2xy)^{2}[/tex]

when, x = 8, and  y = 3

[tex](8^{2} + 3^{2} )^{2}[/tex] = [tex](8^{2} - 3^{2}) ^{2}[/tex]  + [tex](2.8.3)^{2}[/tex]

               = 3025 + 2304

               = 5329

Hence ,Pythagorean triple is 5329

To learn more about Pythagorean triple from here

https://brainly.in/question/21789673

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