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Sagot :
A) You can have
1-1; 1-2; 1-3; 1-4; 1-5; 1-6; 2-2; 2-3; 2-4; 2-5; 2-6; 3-3; 3-4; 3-5; 3-6; 4-4; 4-5; 4-6; 5-5; 5-6; 6-6
Those are all possible outcomes
B) Only 6 of the options include at least one three
The fraction is: 6/21 or simplified 2/7
C) To find this answer we need a percentage
to find that...
6/21 and ?/100
(When writing put it as a fraction to visually see the next part)
We will cross-multiply: the ? will be represented by x
(6 times 100) + (21x)
600 = 21x
Now divide 600 by 21 to get about 28.6
Since 28.6 < 34 then we would get a probability of less than 34 out of 100
Give brainliest to other person lol. I answered ur other question on the same thing tho
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