Answer:
643 °C
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 268 mL
Initial temperature (T₁) = 25 °C
Final volume (V₂) = 824 mL
Final temperature (T₂) =?
Next, we shall convert 25 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 25 °C
T(K) = 25 + 273
T(K) = 298 K
Next, we shall determine the final temperature. This can be obtained as follow:
Initial volume (V₁) = 268 mL
Initial temperature (T₁) = 298 K
Final volume (V₂) = 824 mL
Final temperature (T₂) =?
V₁/T₁ = V₂/T₂
268 / 298 = 824 / T₂
Cross multiply
268 × T₂ = 298 × 824
268 × T₂ = 245552
Divide both side by 268
T₂ = 245552 / 268
T₂ ≈ 916 K
Finally, we shall convert 916 K to celsius temperature. This can be obtained:
T(°C) = T(K) – 273
T(K) = 916 K
T(°C) = 916 – 273
T(°C) = 643 °C
Therefore, the final temperature is 643 °C
