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Answered

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IF ANYONE HAS THE ANSWERS TO ANYOF THESE PLEASE I NEED THEM RLLY BAD :(
its BalancingChemEquations part B gizmo

IF ANYONE HAS THE ANSWERS TO ANYOF THESE PLEASE I NEED THEM RLLY BAD Its BalancingChemEquations Part B Gizmo class=

Sagot :

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Answer:

For the second to last problem the coefficients is  1, 5, 3, and 4 and the last problem all the coefficients are 1's

Explanation:

For the second to last problem you put 3 next to CO₂ so C is 3 on both sides. Then you put 4 next to H₂O because H will then be 8 on both sides. Lastly you put 5 next to O₂ which will make 10 on the reactant side. On the product side the 3 next to CO₂ will make O on the product side 6 and the 4 next to H₂O will make O on the product side 4. You will then add both together and it will make 10, which will make 10 on both sides. Hope this helps!

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