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Sagot :
Answer:
1. 22
2. 7*3=21
3. 2
4. 8
Step-by-step explanation: (I am not sure what level math you are as you put HS but I used simple algebra in my answers)
1. Using algebra I put the missing variable as x.
"add 5 to me" is x+5.
"divide by 9, you get 3"
[tex]\frac{x+5}{9}[/tex] = 3
Begin solving by multiplying 9 to the 3 on the other side
x+5 = 27
Subtract 5 to get x by itself
x = 22
2. An equivalent multiplication sentence can be found using algebra.
21 ÷ 7 = 3 can be rewritten as [tex]\frac{21}{7} =3[/tex]
Using algebra we know if we multiply 7 onto both sides we end up with
7*3=21
3.
Combined total of 16 fumbles
8 players
Same amount of fumbles
How many fumbles per player?
I would draw this out. You have 8 players and 16 fumbles to allocate to them. You can draw tallies and allocate them to each player. You'll find that the first time they all have the equal amount is when they all have 1 fumble. The next time they all have an equal amount they'll have 2 per and all 16 will be used.
4. Algebra
[tex]\frac{x * 7 - 2}{6} =9[/tex]
First is multiplication: x*7 = 7x
[tex]\frac{7x - 2}{6} =9[/tex]
Then division: Multiply the 6 over because we don't like fractions
[tex]{7x - 2} = 54[/tex]
Next we add the 2 over
[tex]{7x } = 56[/tex]
Then divide by 7 to solve for x
x=8
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