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Two cars leave towns 360 kilometers apart at the same time and travel toward each other. One car’s rate is 10 kilometers per hour less than the others. If they meet in 2 hours what is the rate of the slower car

Sagot :

sqdancefan

9514 1404 393

Answer:

  85 km/h

Step-by-step explanation:

Let s represent the speed of the slower car. Then the travel time is ...

  time = distance/speed

  2 = 360/(s +(s+10))

  4s +20 = 360 . . . . . multiply by 2s+10

  4s = 340 . . . . . . . . . subtract 20

  s = 85 . . . . . . . . . . . divide by 4

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The rate of the slower car is 85 km/h.

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