Answered

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A 3.0-A current is maintained in a simple circuit that consists of a resistor between the terminals of an ideal battery. If the battery supplies energy at a rate of 25 W, how large is the resistance

Sagot :

Answer:

[tex]R=2.78\ \Omega[/tex]

Explanation:

Given that,

The current flowing in the circuit, I = 3 A

The power of the battery, P = 25 W

We need to find the resistance of the battery. We know that the power of the battery is given by the formula as follows :

[tex]P=I^2R[/tex]

Put all the values to find R.

[tex]R=\dfrac{P}{I^2}\\\\R=\dfrac{25}{(3)^2}\\\\R=2.78\ \Omega[/tex]

So, the resistance is equal to [tex]2.78\ \Omega[/tex].

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