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Sagot :
Answer:
Balanced equation:
CaCO3 (s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)
1mol CaCO3 will react with 2 mol HCl
Mol HCl in 32.8mL of 1.25M solution = 32.8mL / 1000mL/L * 1.25mol /L = 0.041 mol HCl
This will react with 0.041/2 = 0.0205 mol CaCO3
Molar mass CaCO3 = 100g/mol
Mass of CaCO3 reacted = 0.0205mol *100g/mol = 2.05g CaCO3.
Grams are the unit of weight or mass that depicts the quantity of a substance. The mass of calcium carbonate reacted is 2.05 gm.
What is mass?
Mass is the product of the moles of the compound and its molar mass, it is given in grams.
The balanced chemical reaction is given as:
[tex]\rm CaCO_{3} (s) + 2HCl(aq) \rightarrow CaCl_{2}(aq) + CO_{2}(g) + H_{2}O(l)[/tex]
From the reaction, 1 mole of calcium carbonate reacts with 2 moles of hydrochloric acid.
Moles of hydrochloric acid is calculated as:
[tex]\begin{aligned} \rm n &= \rm Molarity \times Volume (L)\\\\&= 0.0328 \times 1.25\\\\&= 0.041\;\rm mol\end{aligned}[/tex]
Now, the moles of calcium carbonate it will react with will be 0.0205 moles.
Mass of calcium carbonate is calculated as:
[tex]\begin{aligned} \rm mass &= \rm molar\; mass \times moles\\\\&= 0.0205 \times 100\\\\&= 2.05 \; \rm g\end{aligned}[/tex]
Therefore, 2.05 gm of calcium carbonate is needed to react with 15.2 gm of hydrochloric acid.
Learn more about mass here:
https://brainly.com/question/9920325
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