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A man who works for a moving company is loading a box onto a moving van. He pushes a 200N box up a 5m long ramp. If he pushes with a force of 60N and the ramp is 1m high, what is the efficiency of the inclined plane

Sagot :

hamzaahmeds

Answer:

η = 0.667 = 66.7%

Explanation:

The efficiency of the man can be given by the following formula:

η = output/input

where,

η = efficiency of man = ?

output = potential energy gain of the box = Wh

input = work done by man = Fd

Therefore,

[tex]\eta = \frac{Wh}{Fd}[/tex]

where,

W = weight of box = 200 N

h = height gained by box = 1 m

F = force exerted by man = 60 N

d = length of ramp = 5 m

Therefore,

[tex]\eta = \frac{(200\ N)(1\ m)}{(60\ N)(5\ m)}[/tex]

η = 0.667 = 66.7%

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