Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Write an equation of a line that passes through the point (2,6) and is parallel to the line y = -3

Sagot :

Answer:

y=6

Step-by-step explanation:

Let us start with the general equation of a line, y=mx+b. m represents the slope of the line, b represents the y intercept, and the y and x represents the values of the coordinate that the line passes through.

In this case, we know our line is parallel to y=-3, thus it has the same slope as it. Notice that in y=-3, there is no x. Therefore, the slope must be 0!

We now have equation:

[tex]y=0x+b[/tex]

Let us plug in the coordinate it passes through (2,6), to solve for b.

[tex]6=0*2+b\\6=b\\[/tex]

Now we have everything! Let us write the equation of the line now.

[tex]y=6[/tex]

I hope this helps! Let me know if you have any questions :)