Answered

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A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is

Sagot :

MrRoyal

Answer:

[tex]r =5[/tex]

Step-by-step explanation:

Given

[tex](h,k) = (-3,2)[/tex] -- center

[tex](x,y) = (1,5)[/tex] --- pass through

Required

The radius (r)

The equation of circle is:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

So, we have:

[tex](1 - -3)^2 + (5 - 2)^2 = r^2[/tex]

[tex](4)^2 + (3)^2 = r^2[/tex]

[tex]16+9 = r^2[/tex]

[tex]25 = r^2[/tex]

Take square roots of both sides

[tex]5 = r[/tex]

[tex]r =5[/tex]

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